A population of white oak trees with 500 individuals and a carrying capacity of 1,500 follows logistic growth. Under ideal low-density conditions, its growth rate is 0.15 per year, but it faces competition from a population of 1,000 Chapman oaks with an α of 0.5. What is the expected growth of the population of white oaks in the next year?

Question

Quizplus · Accepted Answer

The logistic growth equation is used: dN/dt = rN(1 - (N + αC)/K). Here, N = 500, K = 1500, r = 0.15, α = 0.5, and C = 1000. Plugging in these values: dN/dt = 0.15 * 500 * (1 - (500 + 0.5*1000)/1500) = 0.15 * 500 * (1 - 1000/1500) = 0.15 * 500 * (1 - 0.6667) = 0.15 * 500 * 0.3333 = 25.

A Population of White Oak Trees with 500 Individuals and a Carrying