The molar Gibbs energy of tribromomethane, CHBr₃, decreases by 4.44 kJ mol^-1 when the temperature is increased from 288 to 308 K. Determine the molar entropy of tribromomethane. A) -222 J K^-1 mol^-1 B) 222 J K^-1 mol^-1 C) 0.222 J K^-1 mol^-1 D) 22.2 J K mol^-1

Question

Quizplus · Accepted Answer

The molar entropy change (ΔS) can be calculated using the relation ΔG = -ΔS * ΔT, where ΔG is the change in Gibbs free energy and ΔT is the change in temperature. Given ΔG = -4.44 kJ/mol and ΔT = 308 K - 288 K = 20 K, solving for ΔS gives ΔS = ΔG / -ΔT = 4.44 kJ/mol / -20 K = 0.222 kJ/K·mol = 222 J/K·mol.

The Molar Gibbs Energy of Tribromomethane, CHBr3, Decreases by 4

The Molar Gibbs Energy of Tribromomethane, CHBr₃, Decreases by 4