The vapour pressure p of liquid diethyl ether, (C₂H₅) ₂O, may be calculated for different temperatures T using the expression
Log (p/bar) =A-B/T
Where, for the temperature range 24 to 48 °C, A = 4.743 and B = 1466.30 K. What is the vapour pressure of liquid diethyl ether at 25 °C?

Question

Quizplus · Accepted Answer

To find the vapour pressure at 25 °C, first convert the temperature to Kelvin: 25 °C = 298.15 K. Then, substitute the values into the given equation: Log(p/bar) = 4.743 - 1466.30 / 298.15. Solving this gives Log(p/bar) ≈ -0.175, which means p ≈ 10^(-0.175) ≈ 0.668 bar.

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