Calculate the change in the chemical potential of a perfect gas when its partial pressure doubles at a temperature of 200°C. A) +2.73 kJ mol^-1 B) +1.15 kJ mol^-1 C) +0.50 kJ mol^-1 D) +0.30 kJ mol^-1

Question

Quizplus · Accepted Answer

The change in chemical potential of a perfect gas is given by:$$\Delta \mu = RT \ln \frac{P_2}{P_1}$$where:* R is the ideal gas constant (8.314 J mol^-1 K^-1)* T is the temperature (200°C = 473 K)* P_1 is the initial partial pressure* P_2 is the final partial pressureWhen the partial pressure doubles, P_2 = 2P_1. Substituting these values into the equation, we get:$$\Delta \mu = RT \ln \frac{2P_1}{P_1} = RT \ln 2 = (8.314 J mol^-1 K^-1)(473 K) \ln 2 = 2728 J mol^-1 = 2.73 kJ mol^-1$$Therefore, the correct answer is A) +2.73 kJ mol^-1.

Calculate the Change in the Chemical Potential of a Perfect