An ideal solution is prepared by mixing 15.6 g of toluene, C6H5CH3, and 136.2 g of butan-1-ol, C4H9OH at 25 °C. The vapour pressure of pure butan-1-ol is 885 Pa at this temperature. Calculate the partial pressure of butan-1-ol in the vapour above the mixture.
A) 885 Pa
B) 811 Pa
C) 74.6 Pa
D) 90.9 Pa
Correct Answer:
Verified
Q9: Estimate the normal boiling temperature of propan-1-ol,
Q10: For the equilibrium
CaCO3(s) ∏ CaO(s) + CO2(g)
How
Q11: When 15.0 cm3 of benzene, C6H6, is
Q12: Calculate the change in the chemical potential
Q13: Determine the molar Gibbs energy of mixing
Q15: The Henry's law constant for pentan-3-one, C2H5COC2H5,
Q16: What partial pressure of hydrogen, H2, is
Q17: Estimate the change in the normal boiling
Q18: Calculate the mass of sodium chloride, NaCl,
Q19: Use the following data for the
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents