An achiral alkene A with the molecular formula C8H16 reacts with B2H6, then H2O2/−OH, to give a single alcohol B, C8H18O, that can be resolved into enantiomers. When alkene A is subjected to Hg(OAc)2/H2O, then NaBH4, a single achiral alcohol C is obtained that has different properties from B but has the same formula. Reaction of A with O3, then H2O2/H2O, gives a ketone D (C7H14O) as one product. Catalytic hydrogenation of alkene A yields 3-ethyl-2-methylpentane. Deduce the structures of compounds A, B, C, and D, and be sure each structure is properly labeled.
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