One liter of hydrogen gas is placed in a vacuum. The emission spectrum of hydrogen shows a red line of wavelength 650 nm. What was the energy of the photon that released it?
A)2)9 * 10^-28 J
B)4)1 * 10^-31 J
C)2)9 * 10^-19 J
D)4)1 * 10^-19 J
E)2)9 * 10^-15 J

Question

One liter of hydrogen gas is placed in a vacuum. The emission spectrum of hydrogen shows a red line of wavelength 650 nm. What was the energy of the photon that released it?

Quizplus · Accepted Answer

E=energy (J) H=Planck's constant (6.626*10^-34J*s) f=frequency (1/s) C=speed of light (3.0 * 10⁸m/s) l = wavelength (650nm = 6.5 *10^-7m) Equations E=hf f=c/l *this equation applies in a vacuum Therefore E=hc/l E=(6.26*10^-34J*s) * (3.0 *10⁸ m/s)/(6.5 *10^-7 m) = 2.9 *10^-19 J

One Liter of Hydrogen Gas Is Placed in a Vacuum