The following equation is under thermodynamic control. Assuming a temperature of 273K and using the provided information, find the K_eq:A + B --> CDG_f° (A) = -200 kJ/molDG_f° (B) = -100 kJ/molDG_f° (C) = -50 kJ/mol
A)K_eq = 1.46 * 10^-14
B)K_eq= 1.46 * 10^-38
C)K_eq = 1.46 * 10^-48
D)K_eq = 0.83 * 10^-27
E)K_eq = 0.83 * 10^-32

Question

Quizplus · Accepted Answer

Under thermodynamic control, the following equation applies: ln (K_eq ) = -DG_rxn °/(R*T) R=ideal gas constant = 8.314 J/mol K DG_rxn°=DG_Gproducts° - DG_Gproducts° DG_rxn° = [-50 kJ/mol * 1mol] - [-100kJ/mol * 1mol - 200kJ/mol * 1 mol] = 250 kJ = 250,000J ln (K_eq ) = -(250,000J)/((8.314J/mol K)*(273K)) solving for K_eq = 1.46 * 10^-48

The Following Equation Is Under Thermodynamic Control