Horizontal distance traveled by a ball if it's thrown with initial velocity of 20ms^-1 at an angle of 30° is A)24 m B)56 m C)35.3 m D)36.3 m

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Quizplus · Accepted Answer

The horizontal distance (range) traveled by a projectile can be calculated using the formula: $ Range = \frac{v^2 \sin 2\theta}{g} $, where $v$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.81 m/s^2$). For an initial velocity of $20 m/s$ and an angle of $30°$, the calculation is as follows: $ Range = \frac{(20)^2 \sin(2 \times 30°)}{9.81} \approx 35.3 m $.

Horizontal Distance Traveled by a Ball If It's Thrown with Initial