If a car starting from rest reaches a velocity of 18ms^-1 after 6.0 s then its acceleration is A)1ms^-2 B)2ms^-2 C)3ms^-2 D)4ms^-2

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Quizplus · Accepted Answer

Acceleration is calculated using the formula $a = \frac{\Delta v}{\Delta t}$, where $\Delta v$ is the change in velocity and $\Delta t$ is the change in time. Here, $\Delta v = 18 \, \text{m/s}$ and $\Delta t = 6.0 \, \text{s}$, so $a = \frac{18 \, \text{m/s}}{6.0 \, \text{s}} = 3 \, \text{m/s}^2$.

If a Car Starting from Rest Reaches a Velocity of 18ms-1

If a Car Starting from Rest Reaches a Velocity of 18ms^-1