If the critical field in a Gunn diode oscillator is 3.2 KV/cm and effective length is 20 microns, then the critical voltage is:

Question

Quizplus · Accepted Answer

The critical voltage (Vc) in a Gunn diode oscillator can be calculated using the formula Vc = E * L, where E is the critical field and L is the effective length. Given E = 3.2 KV/cm (or 3200 V/cm) and L = 20 microns (or 20 x 10^-4 cm), Vc = 3200 V/cm * 20 x 10^-4 cm = 6.4 V.

If the Critical Field in a Gunn Diode Oscillator Is