Calculate the change in entropy of the following equation:
FeCl₃(s) + 3Na(s) --> Fe(s) + 3NaCl(s)

Question

Calculate the change in entropy of the following equation: FeCl₃(s) + 3Na(s) --> Fe(s) + 3NaCl(s)

Quizplus · Accepted Answer

Solution is as follows: DS_rXN° = DS_products° - DS_reactants° Students must look up the DS° for each product and reactant. The numbers are as follows: DS° (FeCl₃_(s)) = 142.3 J/mol K DS° (Na_(s)) = 51.3 J/mol K DS° (Fe_(s)) = 27.2 J/mol K DS° (NaCl_(s)) = 72.3 J/mol K Therefore DS_rXN° = [(1mol * 27.2 J/mol K) + (3mol * 72.3 J/mol K) ] - [ (1mol * 142.3 J/mol K) +(3mol * 51.3 J/mol K)] DS_rXN° = -52.1 J/K ***mole amounts come from the stoichiometry

Calculate the Change in Entropy of the Following Equation