An equation for the tangent line to the curve $y = \left( 7 x ^ { 2 } + x - 1 \right) ^ { 5 }$ at the point where x = 0 is
A) y = 5x + 1
B) y = 5x - 1
C) y = 10x - 1
D) y = 10x + 1

Question

Quizplus · Accepted Answer

To find the tangent line, first find the derivative of $y = (7x^2 + x - 1)^5$ using the chain rule. At $x = 0$, the derivative is 0, and the function value is -1. Thus, the tangent line is $y = 5x - 1$.

An Equation for the Tangent Line to the Curve y=(7x2+x−1)5y = \left( 7 x ^ { 2 } + x - 1 \right) ^ { 5 }y=(7x2+x−1)5

An Equation for the Tangent Line to the Curve $y = \left( 7 x ^ { 2 } + x - 1 \right) ^ { 5 }$