If $f ( x ) = \sqrt { 1 - 3 x ^ { 2 } }$ , then $f ^ { \prime \prime } ( x ) = \frac { - 3 } { \left( 1 - 3 x ^ { 2 } \right) ^ { 3 / 2 } }$ .

Name: If $f ( x ) = \sqrt { 1 - 3 x ^ { 2 } }$ , then $f ^ { \prime \prime } ( x ) = \frac { - 3 } { \left( 1 - 3 x ^ { 2 } \right) ^ { 3 / 2 } }$ .
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The second derivative of $f(x) = \sqrt{1 - 3x^2}$ is actually $f''(x) = \frac{9}{(1 - 3x^2)^{3/2}}$.

If f(x)=1−3x2f ( x ) = \sqrt { 1 - 3 x ^ { 2 } }f(x)=1−3x2​

If $f ( x ) = \sqrt { 1 - 3 x ^ { 2 } }$