What would be the resulting pH if one drop (0.05 ml) of 1.0 M HCl was added to one liter of pure water (assume pH 7.0)?

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Quizplus · Accepted Answer

Adding a small amount of a strong acid like HCl to a large volume of water will slightly decrease the pH, but not drastically. The concentration of HCl after adding 0.05 mL (which is 0.05/1000 L) of 1.0 M solution to 1 L of water is 0.05/1000 * 1.0 M = 5.0 * 10^-5 M. The pH is the negative logarithm of the H+ concentration, so pH = -log(5.0 * 10^-5) = 4.3.

What Would Be the Resulting PH If One Drop (0