Two resistors, 20 $\Omega$ and 30 $\Omega$, are connected in parallel. A third resistor, 24 $\Omega$, is connected in series with the parallel combination. A 36-V power source is connected to the series-parallel combination. The current through the 20- $\Omega$ resistor is

Question

Two resistors, 20  $\Omega$ and 30  $\Omega$, are connected in parallel. A third resistor, 24  $\Omega$, is connected in series with the parallel combination. A 36-V power source is connected to the series-parallel combination. The current through the 20- $\Omega$ resistor is

Quizplus · Accepted Answer

The equivalent resistance of the 20 Ω and 30 Ω resistors in parallel is 12 Ω. Adding the 24 Ω resistor in series gives a total resistance of 36 Ω. The total current from the 36-V source is 1 A. The current through the 20 Ω resistor is the same as the total current through the parallel combination, which is 0.60 A.

Two Resistors, 20 Ω\OmegaΩ And 30 Ω\OmegaΩ , Are Connected in Parallel Ω\OmegaΩ

Two Resistors, 20 $\Omega$ And 30 $\Omega$ , Are Connected in Parallel $\Omega$