Two resistors, 20 $\Omega$ and 30 $\Omega$, are connected in parallel. A third resistor, 24 $\Omega$, is connected in series with the parallel combination. The equivalent resistance of the networks is

Question

Two resistors, 20  $\Omega$ and 30  $\Omega$, are connected in parallel. A third resistor, 24  $\Omega$, is connected in series with the parallel combination. The equivalent resistance of the networks is

Quizplus · Accepted Answer

First, calculate the equivalent resistance of the two resistors in parallel: $1/R_{parallel} = 1/20 + 1/30$, which simplifies to $1/R_{parallel} = 3/60 + 2/60 = 5/60$, so $R_{parallel} = 12 \Omega$. Then, add this to the resistance of the third resistor in series: $R_{total} = R_{parallel} + R_{series} = 12 + 24 = 36 \Omega$.

Two Resistors, 20 Ω\OmegaΩ And 30 Ω\OmegaΩ , Are Connected in Parallel Ω\OmegaΩ

Two Resistors, 20 $\Omega$ And 30 $\Omega$ , Are Connected in Parallel $\Omega$