A uniform electric field is directed along the positive y axis. A net flux of 5.00 $\times$ 10⁴ N.m²/C passes through a surface whose area is 400.0 cm² and is aligned along the x-z plane. The magnitude of the electric field is

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Quizplus · Accepted Answer

The electric flux ($\Phi$) is given by the equation $\Phi = EA\cos(\theta)$, where $E$ is the electric field strength, $A$ is the area through which the field lines pass, and $\theta$ is the angle between the field direction and the normal to the surface. Since the electric field is along the y-axis and the surface is aligned along the x-z plane, $\theta = 0^\circ$, making $\cos(\theta) = 1$. Given $\Phi = 5.00 \times 10^{14} \, \text{N.m}^2/\text{C}$ and $A = 400.0 \, \text{cm}^2 = 400.0 \times 10^{-4} \, \text{m}^2$, solving for $E$ gives $E = \Phi/A = (5.00 \times 10^{14}) / (400.0 \times 10^{-4}) = 1.25 \times 10^{16} \, \text{N/C}$.

A Uniform Electric Field Is Directed Along the Positive Y ×\times×

A Uniform Electric Field Is Directed Along the Positive Y $\times$