A uniform electric field is directed along the positive y axis. If the magnitude of the electric field is 5.00 $\times$ 10⁶ N/C, the electric flux through a 400.0-cm² surface aligned along the x-z plane is

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Quizplus · Accepted Answer

The electric flux, $\Phi_E$, through a surface is given by the formula $\Phi_E = E \cdot A \cdot \cos(\theta)$, where $E$ is the magnitude of the electric field, $A$ is the area of the surface, and $\theta$ is the angle between the electric field direction and the normal to the surface. Since the electric field is along the y-axis and the surface is aligned along the x-z plane, the angle $\theta$ is 0 degrees, making $\cos(\theta) = 1$. The area $A = 400.0 \, \text{cm}^2 = 0.04 \, \text{m}^2$ (since $1 \, \text{cm}^2 = 10^{-4} \, \text{m}^2$). Therefore, $\Phi_E = (5.00 \times 10^6 \, \text{N/C}) \cdot (0.04 \, \text{m}^2) \cdot 1 = 2.00 \times 10^5 \, \text{N}\cdot\text{m}^2/\text{C}$.

A Uniform Electric Field Is Directed Along the Positive Y ×\times×

A Uniform Electric Field Is Directed Along the Positive Y $\times$