A simple harmonic oscillator consists of a 1.0-kg mass connected to a spring whose force constant is 10.0 N/m. When the system is initially displaced 1.00 cm and released, the period is measured to be 2.0 seconds. If the initial displacement is increased to 2.00 cm, the period is measured as
A) 1.4 s.
B) 2.0 s.
C) 2.8 s.
D) 4.0 s.

Question

Quizplus · Accepted Answer

The period of a simple harmonic oscillator is given by $T = 2\pi\sqrt{\frac{m}{k}}$, where $m$ is the mass and $k$ is the spring constant. This formula shows that the period $T$ is independent of the amplitude of the oscillation, so increasing the initial displacement does not change the period.

A Simple Harmonic Oscillator Consists of a 1