An object is moving with simple harmonic motion with an amplitude of 2.5 cm and a maximum acceleration of 1.0 $\times$ 10² m/s². The frequency of the motion is A) 10 Hz. B) 63 Hz. C) 1.0 $\times$ 10² Hz. D) 6.3 Hz.

Question

Quizplus · Accepted Answer

The maximum acceleration of an object in simple harmonic motion is given by a = ω^2A, where ω is the angular frequency and A is the amplitude. Therefore, ω = √(a/A) = √(1.0 × 10^2 m/s^2 / 2.5 × 10^-2 m) = 20 rad/s. The frequency is then given by f = ω/2π = 20 rad/s / 2π rad/s = 10 Hz.

An Object Is Moving with Simple Harmonic Motion with an Amplitude