Silver bromide, AgBr, is more soluble in ammonia solution than in pure water. The reaction is, AgBr(s) + 2 NH3(aq)
Ag(NH3) 2+ + Br-(aq) Using Ksp(AgBr) = 5.0 × 10-13 and Kform (Ag(NH3) 2+) = 1.60 × 107, calculate the solubility of AgBr in 0.800 M ammonia solution..Hint: Combine the formation and solubility reactions to find the overall reaction and its equilibrium constant, and make sure to account for the presence of a common ion.
A) 1.6 × 10-3 M
B) 2.3 × 10-3 M
C) 2.8 × 10-3 M
D) 4.2 × 10-3 M
E) 6.1 × 10-2 M
Correct Answer:
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