The reaction, 2A2X4(g) 2A2X3(g) + X2(g) , was found to be first order. The rate law, therefore, should be:
A) rate = k([A2X3]2[X2]) /[A2X4]2
B) rate = k[A2X4]2
C) rate = k([A2X3][X2]) /[A2X4]
D) rate = k[A2X4]
E) rate = k[A2X4]2/([A2X3]2[X2])
Correct Answer:
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