For a given chemical reaction, the rate constant at 42.0 °C is 0.00395 s^-¹, while the rate constant at 67.4 °C is 0.0133 s^-¹. Calculate the value of the activation energy, in kilojoules per mole.

Question

Quizplus · Accepted Answer

The activation energy can be calculated using the Arrhenius equation: ln(k2/k1) = (Ea/R) * (1/T1 - 1/T2). By substituting the given rate constants and temperatures (converted to Kelvin), the activation energy (Ea) is found to be approximately 42.6 kJ/mol.

For a Given Chemical Reaction, the Rate Constant at 42