A glucose solution is prepared by dissolving 5.10 g of glucose, C₆H₁₂O₆, in 110.5 g of water. What is the molality of the glucose solution?

Question

Quizplus · Accepted Answer

Molality (m) is calculated by dividing the moles of solute by the kilograms of solvent. The moles of glucose is 5.10 g / 180.18 g/mol = 0.0283 mol. The mass of water is 110.5 g = 0.1105 kg. Molality = 0.0283 mol / 0.1105 kg = 0.256 m.

A Glucose Solution Is Prepared by Dissolving 5