A solution is prepared by mixing 0.3355 moles of NaNO₃ (84.995 g mol^-1)with 235.0 g of water (18.015 g mol^-1). Its density is 1.0733 g mL^-1. What is the percent by mass of NaNO₃ in the solution?

Question

Quizplus · Accepted Answer

The percent by mass is calculated by dividing the mass of NaNO3 by the total mass of the solution and multiplying by 100. The mass of NaNO3 is 0.3355 moles * 84.995 g/mol = 28.52 g. The total mass of the solution is 28.52 g + 235.0 g = 263.52 g. Thus, the percent by mass is (28.52 g / 263.52 g) * 100 = 10.82%.

A Solution Is Prepared by Mixing 0