A 113.25 gram sample of gold is initially at 100.0 °C. It loses 20.00 J of heat to its surroundings. What is its final temperature? (specific heat of gold = 0.129 J g^-1 °C^-1)

Question

Quizplus · Accepted Answer

Explanation:Heat lost by gold = mass × specific heat × change in temperature20.00 J = 113.25 g × 0.129 J g^-1 °C^-1 × (100.0 °C - final temperature)Final temperature = 98.6 °C

A 11325 Gram Sample of Gold Is Initially at 100