Use the following equations for Questions
c = 3.0 x10 8 m/s = $\lambda$$\nu$;E = h$\nu$; h = 6.626 x 10 -34 J.s
E = h$\nu$ - h$\nu$ 0 ; E = ½ mv 2 (KE of an electron) mass e = 9.11 x 10 -31 kg
-Sodium emits yellow light of wavelength 690nm when heated in a flame. What is the frequency of this light?

Question

Use the following equations for Questions 
c = 3.0 x10 8 m/s = $\lambda$$\nu$;E = h$\nu$; h = 6.626 x 10 -34 J.s
E = h$\nu$ - h$\nu$ 0 ; E = ½ mv 2 (KE of an electron) mass e = 9.11 x 10 -31 kg
-Sodium emits yellow light of wavelength 690nm when heated in a flame. What is the frequency of this light?

Quizplus · Accepted Answer

The frequency ($\nu$) can be calculated using the equation $c = \lambda \nu$, where $c$ is the speed of light (3.0 x 10^8 m/s) and $\lambda$ is the wavelength (690 nm = 690 x 10^-9 m). Solving for $\nu$ gives approximately 4.35 x 10^14 s^-1.

Use the Following Equations for Questions C = 3 λ\lambdaλ

Use the Following Equations for Questions
C = 3 $\lambda$