Use the following equations for Questions
c = 3.0 x10⁸m/s = $\lambda$ $\nu$ ;E = h $\nu$ ; h = 6.626 x 10^-34 J.s
E = h $\nu$ - h $\nu$ ₀; E = ½ mv² (KE of an electron) mass_e = 9.11 x 10^-31 kg
-Chromium metal has a binding energy of 7.21 x 10^-19J for certain electrons. What is the photon frequency needed to eject electrons with 2.2 x 10^-19J of energy?

Question

Use the following equations for Questions
c = 3.0 x10⁸m/s =

\lambda

\nu

;E = h

\nu

; h = 6.626 x 10^-34 J.s
E = h

\nu

- h

\nu

₀; E = ½ mv² (KE of an electron) mass_e = 9.11 x 10^-31 kg
-Chromium metal has a binding energy of 7.21 x 10^-19J for certain electrons. What is the photon frequency needed to eject electrons with 2.2 x 10^-19J of energy?

Quizplus · Accepted Answer

The total energy required to eject the electron is the sum of the binding energy and the energy given to the electron, which is $7.21 \times 10^{-19} J + 2.2 \times 10^{-19} J = 9.41 \times 10^{-19} J$. Using the equation $E = h\nu$, where $h = 6.626 \times 10^{-34} J\cdot s$, we can solve for the frequency $\nu$:$$\nu = \frac{E}{h} = \frac{9.41 \times 10^{-19} J}{6.626 \times 10^{-34} J\cdot s} \approx 1.4 \times 10^{15} s^{-1}$$

Use the Following Equations for Questions C = 3 λ\lambdaλ

Use the Following Equations for Questions
C = 3 $\lambda$