Question 1

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3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-What is the temperature of liquid nitrogen in ˚F, if the nitrogen is currently at -195.8 ˚C?

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3.785 L...

Question 2

Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -A flask with a mass of 160.342 g is filled with 22° C water. The mass of the flask filled with water is found to be 310.5 g. Given that the density of water at 22°C is 0.99780 g/cm³, what is the volume of the flask?

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3.785 L...

Question 3

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3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-Fill in the missing quantity:

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3.785 L...

Question 4

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3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-When you fill up your car in a country in Europe, your credit card is charged $25.45 for 32.3 L of gasoline. What is the price of gasoline in dollars per gallon?

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3.785 L...

Question 5

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3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-Rhodium metal recently was selling for $105.15 per gram. What is the price for a pound of rhodium metal in dollars?

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3.785 L...

Question 6

Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -It has been said that 3.0 kg of plutonium is enough to make an atomic bomb. If you were working security at an airport, just how large of a metallic object would you be looking for? That is, determine the diameter (in cm) of a sphere of plutonium that has a mass of 3.0 kg. (the density of plutonium is 19.84 g/cm³)

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3.785 L...

Question 7

Use the following information for Questions
3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-You are asked to administer 4.9 g of an injectable solution which contains 0.23 % of a lifesaving drug by mass. The syringe has graduations of 0.1 mL. If the density of the solution is 1.13 g/mL, how many mL should you inject?

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3.785 L...

Question 8

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3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-Ethyl ether has a density of 0.7138 g/ml. How many litres will be needed to obtain 500 grams of ethyl ether for a reaction?

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3.785 L...

Question 9

Use the following information for Questions
3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32)
‪ 
-The density of mercury is 13.6 g/ml and the density of water is 1.00 g/ml. How many meters high would a column of water need to be, to be equal in mass to a column of mercury 750 mm high? (assume the columns of liquid have the same diameter)

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3.785 L...

Question 10

Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -What is the difference in mass between 1.000 x 10¹⁵ protons and the same number of neutrons? What is the electrical charge (in coulombs) carried by this number of protons?

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3.785 L...

Question 11

Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πrS1U1P13S1S1P0S1U1P1;S1S1P0 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -What is the mass of 1.000 x 10¹⁵ electrons? What is the electrical charge (in coulombs) carried by this number of electrons?

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Question 12

Use the following information for Questions .
1 mole = 6.022 x10S1U1P123S1S1P0 particles
-Which would have a greater mass: 1.25 mole sample of lead or 11.25 mole sample of aluminum?

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1...

Question 13

Use the following information for Questions .
1 mole = 6.022 x10S1U1P123S1S1P0 particles
-Which would have a greater mass: a 1.75 mole sample of tin or a 5.25 mole sample of aluminum?

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Question 14

Use the following information for Questions .
1 mole = 6.022 x10S1U1P123S1S1P0 particles
-Which would have a greater mass: a 2.37 mole sample of potassium or a 3.72 mole sample of magnesium?

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Question 15

Use the following information for Questions . 1 mole = 6.022 x10S1U1P123S1S1P0 particles -Naturally occurring platinum has several different isotopes, ¹⁹⁰Pt (0.0127%; 189.960 amu); ¹⁹²Pt (0.78 %; 191.9614 amu); ¹⁹⁴Pt (32.9%; 193.9628 amu), ¹⁹⁵Pt (33.8 %; 194.9648 amu); ¹⁹⁶Pt (25.3 %; 195.9650 amu) and ¹⁹⁸Pt (7.21 %; 197.9675 amu). What is the molar mass of naturally occurring platinum?

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Question 16

Use the following information for Questions . 1 mole = 6.022 x10S1U1P123S1S1P0 particles -The density of a particular 300 cm³ graphite sample is 2.16 g cm^-3; how many atoms are contained in the sample?

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Question 17

Use the following information for Questions . 1 mole = 6.022 x10S1U1P123S1S1P0 particles -What volume is occupied by an iron sample containing 7.2 x 10²⁵ atoms if the density of the sample is 7.87 g cm³?

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1...

Question 18

Calculate the number of moles of carbon atoms and moles of sulphur atoms in 50.0 g of CS₂.

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Question 19

Draw a ball and stick model of 1,6-hexanediamine, a starting material for nylon. The line structure is shown below:

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Question 20

Determine the molecular formula and draw the line structure for 2-bromobutane.

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Quiz 1: Fundamental Concepts of Chemistry

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -Which would have a greater mass: 1.25 mole sample of lead or 11.25 mole sample of aluminum?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -Which would have a greater mass: a 1.75 mole sample of tin or a 5.25 mole sample of aluminum?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -Which would have a greater mass: a 2.37 mole sample of potassium or a 3.72 mole sample of magnesium?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -The density of a particular 300 cm³ graphite sample is 2.16 g cm^-3; how many atoms are contained in the sample?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -What volume is occupied by an iron sample containing 7.2 x 10²⁵ atoms if the density of the sample is 7.87 g cm³?

Calculate the number of moles of carbon atoms and moles of sulphur atoms in 50.0 g of CS₂.

Draw a ball and stick model of 1,6-hexanediamine, a starting material for nylon. The line structure is shown below:

Determine the molecular formula and draw the line structure for 2-bromobutane.

Quiz 1: Fundamental Concepts of Chemistry

Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πr3; 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -Fill in the missing quantity:

Use the following information for Questions . 1 mole = 6.022 x1023 particles -Which would have a greater mass: 1.25 mole sample of lead or 11.25 mole sample of aluminum?

Use the following information for Questions . 1 mole = 6.022 x1023 particles -Which would have a greater mass: a 1.75 mole sample of tin or a 5.25 mole sample of aluminum?

Use the following information for Questions . 1 mole = 6.022 x1023 particles -Which would have a greater mass: a 2.37 mole sample of potassium or a 3.72 mole sample of magnesium?

Use the following information for Questions . 1 mole = 6.022 x1023 particles -The density of a particular 300 cm3 graphite sample is 2.16 g cm-3; how many atoms are contained in the sample?

Use the following information for Questions . 1 mole = 6.022 x1023 particles -What volume is occupied by an iron sample containing 7.2 x 1025 atoms if the density of the sample is 7.87 g cm3?

Calculate the number of moles of carbon atoms and moles of sulphur atoms in 50.0 g of CS2.

Draw a ball and stick model of 1,6-hexanediamine, a starting material for nylon. The line structure is shown below:

Determine the molecular formula and draw the line structure for 2-bromobutane.

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -Which would have a greater mass: 1.25 mole sample of lead or 11.25 mole sample of aluminum?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -Which would have a greater mass: a 1.75 mole sample of tin or a 5.25 mole sample of aluminum?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -Which would have a greater mass: a 2.37 mole sample of potassium or a 3.72 mole sample of magnesium?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -The density of a particular 300 cm³ graphite sample is 2.16 g cm^-3; how many atoms are contained in the sample?

Use the following information for Questions . 1 mole = 6.022 x10²³ particles -What volume is occupied by an iron sample containing 7.2 x 10²⁵ atoms if the density of the sample is 7.87 g cm³?

Calculate the number of moles of carbon atoms and moles of sulphur atoms in 50.0 g of CS₂.