Question 1

Figure 20-1 -Refer to Figure 20-1 (a). If R₁ = R₂ = 30 k? and the closed loop gain is 450, the value of the external gain-setting resistor R_G is: A) 13.4 ?. B) 134 ?. C) 134 k?. D) none of the above.

Accepted Answer

B

Question 2

The voltage gain of an OTA can be calculated using the formula: A) A_V= g_mR_L. B) A_V= 2 Rf/R_i. C) A_V= R_f/R_i. D) A_V= (R_f/R_i)₊1.

Accepted Answer

The formula for the voltage gain of an Operational Transconductance Amplifier (OTA) typically involves transconductance (g_m) and load resistance (R_L), which is closest to option A, although the formula presented is not standard notation.

Question 3

Figure 19-2
-If the inputs are 1.2 V, -0.5 V and 2.4 V in Figure 19-2(b), what is the output voltage?
A) -4.1 V
B) -6.2 V
C) 6.2 V
D) 13 V

Accepted Answer

The output voltage of an operational amplifier in a summing configuration can be calculated using the formula Vout = -Rf*(V1/R1 + V2/R2 + V3/R3 + ...), where Rf is the feedback resistor, and V1, V2, V3, etc., are the input voltages with their respective resistors R1, R2, R3, etc. Assuming equal resistances for simplicity, the output voltage for inputs of 1.2 V, -0.5 V, and 2.4 V would be the negative sum of these inputs, resulting in -6.2 V.

Question 4

Figure 19-3 -If V_IN= 70 V_P in Figure 19-3, the output voltage at f_CO equals ________. A) 49.5 V_P B) 0 V_P C) 13 V_P D) 44.2 V_P

Accepted Answer

The output voltage is a percentage of the peak supply voltage (V_P), and given that 70% (from the equation) is the correct operation point, the output voltage at the specified condition would be 49.5% of V_P, which corresponds to choice A.

Question 5

The output of an op-amp differentiator depends on the values of ________ and ________. A) R_IN, C_F B) C_IN, C_F C) C_IN, R_F D) R_IN, R_F

Accepted Answer

The output of an op-amp differentiator depends on the values of the capacitor (C) and the resistor (R).

Question 6

Figure 18-1 -If R_f = 1.2 M? and A_V = 120 in Figure 18-1(c), R_i equals ________. A) 100 k? B) 120 ? C) 1 k? D) 10 k?

Accepted Answer

The voltage gain (A_V) of an inverting amplifier is given by the formula A_V = -R_f/R_i. Given A_V = 120 and R_f = 1.2 MΩ, solving for R_i gives R_i = R_f/A_V = 1.2 MΩ / 120 = 10 kΩ.

Question 7

Figure 18-1 -V_RF equals ________ in Figure 18-1(c). A) V_CC B) V_RI C) V_IN D) V_OUT

Accepted Answer

The answer of Figure 18-1 -V_RF equals ________ in Figure...

Question 8

Figure 18-1 -If R_f = 150 k? and R_i = 2.2 k? in Figure 18-1(c), the voltage gain equals ________. A) -69.2 B) -68.2 C) -1 D) infinite

Accepted Answer

The answer of Figure 18-1 -If R_f = 150 k?...

Question 9

Figure 18-1 -If R_f = 1.2 M? and R_i = 47 k? in Figure 18-1(b), the voltage gain equals ________. A) 25 B) 26 C) 26.5 D) 25.5

Accepted Answer

The answer of Figure 18-1 -If R_f = 1.2 M?...

Question 10

Figure 18-1 -If R_f= 100 k? and A_V = (-833) in Figure 18-1(c), R_i equals ________. A) 10 k? B) 1 k? C) 100 k? D) 120 ?

Accepted Answer

The answer of Figure 18-1 -If R_f= 100 k? and...

Question 11

Figure 18-1 -If R_f = 5 k? and R_i = 10 k? in Figure 18-1(c), the voltage gain equals ________. A) -5 B) -2 C) 0 D) -0.5

Accepted Answer

The voltage gain (A) for an inverting amplifier is given by the formula A = -R_f/R_i. Substituting the given values, A = -5 kΩ / 10 kΩ = -0.5.

Question 12

Voltage gain can be found by A_V = V_IN ÷ V_OUT

Accepted Answer

The given formula appears to be a mix of symbols and does not represent a standard equation for calculating voltage gain, which is typically found using the formula Voltage Gain (AV) = Vout / Vin, where Vout is the output voltage and Vin is the input voltage.

Question 13

On transistor spec sheet, the key difference between ?_DC and ?_DC is that: A) ?_DC represents I_C/I_B; ?_DC represents I_C/I_E. B) ?_DC represents I_E/I_C; ?_DC represents I_B/I_C. C) ?_DC represents I_E/I_C; ?_DC represents I_C/I_E. D) ?_DC represents I_C/I_B; ?_DC represents I_B/I_c.

Accepted Answer

The question seems to contain placeholders or coded text rather than actual specifications, making it impossible to provide a factual explanation. However, in general, transistor spec sheets detail parameters like current gain, which is the ratio of output current to input current, and these ratios differ based on the configuration (common base, common emitter, etc.).

Quiz 6: Basic Op-Amp Circuits, Special-Purpose Op-Amp Circuits, the Operational Amplifier, Transistors and Applications

Figure 20-1 -Refer to Figure 20-1 (a) . If R₁ = R₂ = 30 k? and the closed loop gain is 450, the value of the external gain-setting resistor R_G is:

The voltage gain of an OTA can be calculated using the formula:

Figure 19-2 -If the inputs are 1.2 V, -0.5 V and 2.4 V in Figure 19-2(b) , what is the output voltage?

Figure 19-3 -If V_IN= 70 V_P in Figure 19-3, the output voltage at f_CO equals ________.

The output of an op-amp differentiator depends on the values of and .

Figure 18-1 -If R_f = 1.2 M? and A_V = 120 in Figure 18-1(c) , R_i equals ________.

Figure 18-1 -V_RF equals ________ in Figure 18-1(c) .

Figure 18-1 -If R_f = 150 k? and R_i = 2.2 k? in Figure 18-1(c) , the voltage gain equals ________.

Figure 18-1 -If R_f = 1.2 M? and R_i = 47 k? in Figure 18-1(b) , the voltage gain equals ________.

Figure 18-1 -If R_f= 100 k? and A_V = (-833) in Figure 18-1(c) , R_i equals ________.

Figure 18-1 -If R_f = 5 k? and R_i = 10 k? in Figure 18-1(c) , the voltage gain equals ________.

Voltage gain can be found by A_V = V_IN ÷ V_OUT

On transistor spec sheet, the key difference between ?_DC and ?_DC is that:

Quiz 6: Basic Op-Amp Circuits, Special-Purpose Op-Amp Circuits, the Operational Amplifier, Transistors and Applications

Figure 20-1 -Refer to Figure 20-1 (a) . If R1 = R2 = 30 k? and the closed loop gain is 450, the value of the external gain-setting resistor RG is:

The voltage gain of an OTA can be calculated using the formula:

Figure 19-2 -If the inputs are 1.2 V, -0.5 V and 2.4 V in Figure 19-2(b) , what is the output voltage?

Figure 19-3 -If VIN= 70 VP in Figure 19-3, the output voltage at fCO equals ________.

The output of an op-amp differentiator depends on the values of ________ and ________.

Figure 18-1 -If Rf = 1.2 M? and AV = 120 in Figure 18-1(c) , Ri equals ________.

Figure 18-1 -VRF equals ________ in Figure 18-1(c) .

Figure 18-1 -If Rf = 150 k? and Ri = 2.2 k? in Figure 18-1(c) , the voltage gain equals ________.

Figure 18-1 -If Rf = 1.2 M? and Ri = 47 k? in Figure 18-1(b) , the voltage gain equals ________.

Figure 18-1 -If Rf= 100 k? and AV = (-833) in Figure 18-1(c) , Ri equals ________.

Figure 18-1 -If Rf = 5 k? and Ri = 10 k? in Figure 18-1(c) , the voltage gain equals ________.

Voltage gain can be found by AV = VIN ÷ VOUT

On transistor spec sheet, the key difference between ?DC and ?DC is that:

Figure 20-1 -Refer to Figure 20-1 (a) . If R₁ = R₂ = 30 k? and the closed loop gain is 450, the value of the external gain-setting resistor R_G is:

Figure 19-3 -If V_IN= 70 V_P in Figure 19-3, the output voltage at f_CO equals ________.

The output of an op-amp differentiator depends on the values of and .

Figure 18-1 -If R_f = 1.2 M? and A_V = 120 in Figure 18-1(c) , R_i equals ________.

Figure 18-1 -V_RF equals ________ in Figure 18-1(c) .

Figure 18-1 -If R_f = 150 k? and R_i = 2.2 k? in Figure 18-1(c) , the voltage gain equals ________.

Figure 18-1 -If R_f = 1.2 M? and R_i = 47 k? in Figure 18-1(b) , the voltage gain equals ________.

Figure 18-1 -If R_f= 100 k? and A_V = (-833) in Figure 18-1(c) , R_i equals ________.

Figure 18-1 -If R_f = 5 k? and R_i = 10 k? in Figure 18-1(c) , the voltage gain equals ________.

Voltage gain can be found by A_V = V_IN ÷ V_OUT

On transistor spec sheet, the key difference between ?_DC and ?_DC is that: