As the reaction below proceeds, what happens (increase, decrease, or remain constant) to the rate of the forward reaction?
CO(g) + H₂O(g) $\rightarrow$ CO₂(g) + H₂(g)
As the reaction proceeds what happens to the rate of the reverse reaction (CO₂ + H₂ $\rightarrow$ CO + H₂O)?
Explain the above answers using the collision theory for gas-phase reactions.

Question

As the reaction below proceeds, what happens (increase, decrease, or remain constant) to the rate of the forward reaction?
CO(g) + H₂O(g)

\rightarrow

CO₂(g) + H₂(g)
As the reaction proceeds what happens to the rate of the reverse reaction (CO₂ + H₂

\rightarrow

CO + H₂O)?
Explain the above answers using the collision theory for gas-phase reactions.

Quizplus · Accepted Answer

The Answer of As the reaction below proceeds, what happens (increase, decrease, or remain constant) to the rate of the forward reaction? CO(g) + H₂O(g) $\rightarrow$ CO₂(g) + H₂(g) As the reaction proceeds what happens to the rate of the reverse reaction (CO₂ + H₂ $\rightarrow$ CO + H₂O)? Explain the above answers using the collision theory for gas-phase reactions.

As the Reaction Below Proceeds, What Happens (Increase, Decrease, or Remain