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The Equilibrium Constant for the Following Reaction Is Kp =

Question 48

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The equilibrium constant for the following reaction is Kp = 1.0 x 104.
2 NO(g) + O2(g) The equilibrium constant for the following reaction is K<sub>p</sub> = 1.0 x 10<sup>4</sup>. 2 NO(g) + O<sub>2</sub>(g)   2 NO<sub>2</sub>(g) Calculate the equilibrium pressure of oxygen in a system that initially contains 0.50 atm of NO, 0.10 atm of O<sub>2</sub>, and 0.20 atm of NO<sub>2</sub>. 2 NO2(g)
Calculate the equilibrium pressure of oxygen in a system that initially contains 0.50 atm of NO, 0.10 atm of O2, and 0.20 atm of NO2.

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