What is the ratio of the weight of Cl₂ produced at the anode to the weight of Al produced at the cathode when 5 moles of electrons are passed through a molten sample of AlCl₃?

Question

Quizplus · Accepted Answer

The ratio of the weight of Cl₂ produced at the anode to the weight of Al produced at the cathode is equal to the ratio of their molar masses. The molar mass of Cl₂ is 70.9 g/mol, and the molar mass of Al is 26.98 g/mol. Therefore, the ratio of the weight of Cl₂ produced to the weight of Al produced is 70.9 g/mol / 26.98 g/mol = 2.63. This means that for every 1 g of Al produced, 2.63 g of Cl₂ is produced. The closest answer choice to this value is B) about 4 g Cl₂ per 1 g Al.

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