Calculate $\Delta$ wing reaction if 1.00 gram of magnesium reacts with excess fluorine to give off 46.22 kJ of heat.
Mg(s) + F₂(g) $\rightarrow$ MgF₂(s)

Question

Calculate $\Delta$ wing reaction if 1.00 gram of magnesium reacts with excess fluorine to give off 46.22 kJ of heat. Mg(s) + F₂(g) $\rightarrow$ MgF₂(s)

Quizplus · Accepted Answer

The molar mass of Mg is 24.31 g/mol. Therefore, 1.00 g of Mg is 1.00/24.31 = 0.0411 mol. The reaction releases 46.22 kJ for 0.0411 mol, so for 1 mol, it would release 46.22 kJ / 0.0411 mol = 1124.33 kJ/mol.

Calculate Δ\DeltaΔ Wing Reaction If 1 →\rightarrow→ MgF2(s) A) Less Than 300 KJ/molrxn B) Between 300 and with Excess

Calculate $\Delta$ Wing Reaction If 1 $\rightarrow$ MgF₂(s)
A) Less Than 300 KJ/mol_rxn
B) Between 300 and with Excess