The change in enthalpy, $\Delta$H, for the following balanced reaction is 33.2 kJ/mol_rxn. How much heat will be absorbed by the reaction of 1.00 g of N₂ with an excess of oxygen? N₂(g) + 2O₂(g) $\rightarrow$ 2 NO₂(g)

Question

Quizplus · Accepted Answer

To find the heat absorbed by reacting 1.00 g of N2, first calculate the moles of N2 using its molar mass (28.02 g/mol). 1.00 g N2 * (1 mol/28.02 g) = 0.0357 mol N2. Since the enthalpy change is 33.2 kJ/mol for the reaction, the heat absorbed for 0.0357 mol is 0.0357 mol * 33.2 kJ/mol = 1.19 kJ.

The Change in Enthalpy Δ\DeltaΔ H, for the Following Balanced Reaction Is 33

The Change in Enthalpy $\Delta$ H, for the Following Balanced Reaction Is 33