Hydrogen peroxide is a good oxidizing agent because it is a good source of molecular oxygen: 2 H2O2(aq) 2 H2O(l) + O2(g) . Calculate Hrxn° for this reaction from the enthalpies of the following reactions.
2 H2(g) + O2(g) 2 H2O(l) Hrxn° = -571.66 kJ/molrxn
H2(g) + O2(g) H2O2(aq) Hrxn° = -187.8 kJ/molrxn
A) -759.5 kJ/molrxn
B) -383.9 kJ/molrxn
C) -196.0 kJ/molrxn
D) -98.0 kJ/molrxn
E) 196.0 kJ/molrxn
Correct Answer:
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