Calculate Hrxn° for the Reaction
N2(g) + O2(g) 2 NO(g)
from the Enthalpies of the Following Reactions
Calculate Hrxn° for the reaction
N2(g) + O2(g) 2 NO(g)
From the enthalpies of the following reactions.
N2(g) + 2 O2(g) 2 NO2(g) Hrxn° = 66.4 kJ/molrxn
2 NO(g) + O2(g) 2 NO2(g) Hrxn° = -114.2 kJ/molrxn
A) -180.6 kJ/molrxn
B) -47.8 kJ/molrxn
C) 47.8 kJ/molrxn
D) 180.6 kJ/molrxn
E) Hrxn° is impossible to calculate from the information given
Correct Answer:
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