Sucrose, or "cane sugar," has the formula C₁₂H₂₂O₁₁. What weight of carbon dioxide can be produced from 10.0 grams of sucrose and 10.0 grams of oxygen?
C₁₂H₂₂O₁₁(s) + 12 O₂(g) $\rightarrow$ 12 CO₂(g) + 11 H₂O(g)

Question

Sucrose, or "cane sugar," has the formula C₁₂H₂₂O₁₁. What weight of carbon dioxide can be produced from 10.0 grams of sucrose and 10.0 grams of oxygen?
C₁₂H₂₂O₁₁(s) + 12 O₂(g)

\rightarrow

12 CO₂(g) + 11 H₂O(g)

Quizplus · Accepted Answer

10.0 grams of sucrose is 10.0 g / 342.3 g/mol = 0.0292 mol. According to the balanced equation, 0.0292 mol of sucrose will react with 0.350 mol of oxygen and will produce 0.350 mol of carbon dioxide. 0.350 mol of carbon dioxide is 0.350 mol * 44.01 g/mol = 15.4 g.

Sucrose, or "Cane Sugar," Has the Formula C12H22O11 →\rightarrow→ 12 CO2(g) + 11 H2O(g) A) Less Than 5 Grams

Sucrose, or "Cane Sugar," Has the Formula C₁₂H₂₂O₁₁ $\rightarrow$ 12 CO₂(g) + 11 H₂O(g)
A) Less Than 5 Grams