How many grams of CO₂ gas are produced from the combustion of 10.0 grams of isooctane?

2 C₈H₁₈ + 25 O₂ $\rightarrow$ 16 CO₂ + 18 H₂O

Question

How many grams of CO₂ gas are produced from the combustion of 10.0 grams of isooctane? 2 C₈H₁₈ + 25 O₂ $\rightarrow$ 16 CO₂ + 18 H₂O

Quizplus · Accepted Answer

The balanced chemical equation shows that 2 moles of isooctane (C8H18) produce 16 moles of CO2. First, calculate the molar mass of isooctane: (8*12.01) + (18*1.008) = 114.23 g/mol. Then, find how many moles of isooctane 10.0 g represents: 10.0 g / 114.23 g/mol = 0.0875 moles. Since the ratio of isooctane to CO2 is 2:16, this amount of isooctane will produce 0.0875 * (16/2) = 0.7 moles of CO2. Finally, calculate the mass of CO2 produced: 0.7 moles * 44.01 g/mol (molar mass of CO2) = 30.8 g.

How Many Grams of CO2 Gas Are Produced from the Combustion

How Many Grams of CO₂ Gas Are Produced from the Combustion