In the following reaction 10.0 grams of lead sulfide, PbS are allowed to react with 5.00 grams of oxygen, O₂. Determine the limiting reagent, the number of grams of PbO that can be produced and the number of moles of reactant that remains unreacted.
2 PbS(s) + 3 O₂(g) $\rightarrow$ 2 PbO(s) + 2 SO₂(g)

Question

In the following reaction 10.0 grams of lead sulfide, PbS are allowed to react with 5.00 grams of oxygen, O₂. Determine the limiting reagent, the number of grams of PbO that can be produced and the number of moles of reactant that remains unreacted.
2 PbS(s) + 3 O₂(g)

\rightarrow

2 PbO(s) + 2 SO₂(g)

Quizplus · Accepted Answer

The Answer of In the following reaction 10.0 grams of lead sulfide, PbS are allowed to react with 5.00 grams of oxygen, O₂. Determine the limiting reagent, the number of grams of PbO that can be produced and the number of moles of reactant that remains unreacted. 2 PbS(s) + 3 O₂(g) $\rightarrow$ 2 PbO(s) + 2 SO₂(g)

In the Following Reaction 10 →\rightarrow→ 2 PbO(s) + 2 SO2(g)

In the Following Reaction 10 $\rightarrow$ 2 PbO(s) + 2 SO₂(g)