A 15. $\mu$F capacitor is connected to a 50. V battery and becomes fully charged. The battery is removed and a slab of dielectric that completely fills the space between the plates is inserted. If the dielectric has a dielectric constant of 5.0, what is the capacitance of the capacitor after the slab is inserted?

Question

Quizplus · Accepted Answer

The capacitance of a capacitor increases by a factor equal to the dielectric constant when a dielectric is inserted. Therefore, the new capacitance is $15 \mu F \times 5 = 75 \mu F$.

A 15 μ\muμ F Capacitor Is Connected to a 50 μ\muμ F B) 3

A 15 $\mu$ F Capacitor Is Connected to a 50 $\mu$ F
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