Two point charges of + 6.00 $\mu$C and + 9.00 $\mu$C are placed inside a cube of edge length 0.100 m. The net electric flux due to these charges is given by A) 1.69 × 10⁶ Nm²/C B) 4.20 × 10⁶ Nm² /C C) 0.450 × 10⁶ Nm²/C D) 3.80 × 10⁶ Nm²/C E) 0.340 × 10⁶ Nm²/C

Question

Quizplus · Accepted Answer

The net electric flux due to the charges is equal to the total charge divided by the permittivity of free space. The permittivity of free space is 8.85 × 10^-12 C²/Nm². Therefore, the net electric flux is:$$\Phi_{net} = \frac{Q_{net}}{\epsilon_0} = \frac{(6.00 \mu C + 9.00 \mu C)}{8.85 imes 10^{-12} C^2/Nm^2} = 1.69 imes 10^6 Nm^2/C$$

Two Point Charges of + 6 μ\muμ C and + 900 μ\muμ

Two Point Charges of + 6 $\mu$ C and + 900 $\mu$