An object's angular momentum changes by 10 kg-m²/s in 2.0 s. What magnitude average torque acted on this object? A) 10 N-m B) 5 N-m C) 2.5 N-m D) 40 N-m E) 20 N-m

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Quizplus · Accepted Answer

The magnitude of the average torque can be found using the formula $\tau = \frac{\Delta L}{\Delta t}$, where $\Delta L$ is the change in angular momentum and $\Delta t$ is the change in time. Given $\Delta L = 10 \, \text{kg-m}^2/\text{s}$ and $\Delta t = 2.0 \, \text{s}$, the average torque is $\tau = \frac{10}{2} = 5 \, \text{N-m}$.

An Object's Angular Momentum Changes by 10 Kg-M2/s in 2

An Object's Angular Momentum Changes by 10 Kg-M²/s in 2