A $1.56-\mathrm{V}$ battery has an internal resistance of $0.120 \Omega$. What is the maximum current that can be drawn from this battery?
A) $13.0 \mathrm{~A}$
B) $7.50 \mathrm{~A}$
C) infinite (or at least 1000s of amps)
D) $0.190 \mathrm{~A}$
E) $1.56 \mathrm{~A}$

Question

Quizplus · Accepted Answer

The maximum current can be calculated using Ohm's Law, $I = \frac{V}{R}$, where $V$ is the voltage of the battery and $R$ is its internal resistance. Thus, $I = \frac{1.56V}{0.120\Omega} = 13.0A$.

A 1.56−V1.56-\mathrm{V}1.56−V Battery Has an Internal Resistance Of 0.120Ω0.120 \Omega0.120Ω What Is the Maximum Current That Can Be Drawn

A $1.56-\mathrm{V}$ Battery Has an Internal Resistance Of $0.120 \Omega$ What Is the Maximum Current That Can Be Drawn