A $12.0 \mathrm{~V}$ battery is connected across a $4.00 \Omega$ resistor. If the current through the resistor is $2.80 \mathrm{~A}$, what is the terminal voltage of the battery?
A) $11.2 \mathrm{~V}$
B) $11.6 \mathrm{~V}$
C) $9.6 \mathrm{~V}$
D) $12.0 \mathrm{~V}$
E) $12.8 \mathrm{~V}$

Question

Quizplus · Accepted Answer

The terminal voltage of the battery can be calculated using Ohm's Law, $V = IR$, where $V$ is the voltage across the resistor, $I$ is the current through the resistor, and $R$ is the resistance. Substituting the given values, $V = 2.80 \, \text{A} \times 4.00 \, \Omega = 11.2 \, \text{V}$.

A 12.0 V12.0 \mathrm{~V}12.0 V Battery Is Connected Across A 4.00Ω4.00 \Omega4.00Ω Resistor If the Current Through the Resistor Is

A $12.0 \mathrm{~V}$ Battery Is Connected Across A $4.00 \Omega$ Resistor If the Current Through the Resistor Is