$4.0 \mathrm{~kg}$ mass has a velocity of $12 \mathrm{~m} / \mathrm{s}$ to the WEST. The mass experiences a constant acceleration of 2.0 $\mathrm{m} / \mathrm{s}^{2}$ to the WEST for $3.0 \mathrm{sec}$. What is the velocity of the mass at the end of the $3.0 \mathrm{sec}$ interval?
A) $18 \mathrm{~m} / \mathrm{s}$ to the EAST
B) $0.0 \mathrm{~m} / \mathrm{s}$
C) $18 \mathrm{~m} / \mathrm{s}$ to the WEST
D) $6.0 \mathrm{~m} / \mathrm{s}$ to the EAST
E) $6.0 \mathrm{~m} / \mathrm{s}$ to the WEST

Question

Quizplus · Accepted Answer

The final velocity can be calculated using the formula $v = u + at$, where $v$ is the final velocity, $u$ is the initial velocity, $a$ is the acceleration, and $t$ is the time. Substituting the given values: $v = 12 \, \text{m/s (to the WEST)} + (2 \, \text{m/s}^2 \times 3 \, \text{s}) = 12 \, \text{m/s} + 6 \, \text{m/s} = 18 \, \text{m/s}$ to the WEST.

4.0 kg4.0 \mathrm{~kg}4.0 kg Mass Has a Velocity Of 12 m/s12 \mathrm{~m} / \mathrm{s}12 m/s

$4.0 \mathrm{~kg}$ Mass Has a Velocity Of $12 \mathrm{~m} / \mathrm{s}$