A Projectile Is Launched from the Edge of a Cliff $10.0 \mathrm{~m} / \mathrm{s}$

A projectile is launched from the edge of a cliff with a velocity of $10.0 \mathrm{~m} / \mathrm{s}$ at an angle of 30.0 degrees above the horizontal. What is the velocity of the projectile 2.00 seconds later (ignoring air resistance, and assuming it hasn't reached the ground yet) ?

A) $V_{\mathrm{x}}=5.6 \mathrm{~m} / \mathrm{s}, \mathrm{V}_{\mathrm{y}}=-14.6 \mathrm{~m} / \mathrm{s}$
B) $\mathrm{V}_{\mathrm{x}}=14.6 \mathrm{~m} / \mathrm{s}, \mathrm{V}_{\mathrm{y}}=-5.6 \mathrm{~m} / \mathrm{s}$
C) $\mathrm{V}_{\mathrm{x}}=8.7 \mathrm{~m} / \mathrm{s}, \mathrm{V}_{\mathrm{y}}=-14.6 \mathrm{~m} / \mathrm{s}$
D) $\mathrm{V}_{\mathrm{x}}=-14.6 \mathrm{~m} / \mathrm{s}, \mathrm{V}_{\mathrm{y}}=8.7 \mathrm{~m} / \mathrm{s}$
E) $\mathrm{V}_{\mathrm{x}}=-8.7 \mathrm{~m} / \mathrm{s}, \mathrm{V}_{\mathrm{y}}=-14.6 \mathrm{~m} / \mathrm{s}$