A $4.00 \mathrm{~kg}$ mass is moving in a circular path of radius $3.20 \mathrm{~m}$ with a constant linear speed of $6.20 \mathrm{~m} / \mathrm{s}$. The radial force on the mass is
A) $59.0 \mathrm{~N}$ toward the center.
B) $48.1 \mathrm{~N}$ toward the center.
C) $50.5 \mathrm{~N}$ away from the center.
D) $62.3 \mathrm{~N}$ away from the center.
E) $40.2 \mathrm{~N}$ away from the center.

Question

Quizplus · Accepted Answer

The radial (centripetal) force can be calculated using the formula $F = \frac{mv^2}{r}$, where $m = 4.00 \, \text{kg}$, $v = 6.20 \, \text{m/s}$, and $r = 3.20 \, \text{m}$. Plugging these values in gives $F = \frac{(4.00)(6.20)^2}{3.20} = 48.1 \, \text{N}$ toward the center.

A 4.00 kg4.00 \mathrm{~kg}4.00 kg Mass Is Moving in a Circular Path of Radius

A $4.00 \mathrm{~kg}$ Mass Is Moving in a Circular Path of Radius