A $2.60 \mathrm{~kg}$ mass is moving in a circular path with a constant angular speed of $5.50 \mathrm{rad} / \mathrm{sec}$ and with a linear speed of $3.50 \mathrm{~m} / \mathrm{s}$. The magnitude of the radial force on the mass is
A) $50.1 \mathrm{~N}$.
B) $66.7 \mathrm{~N}$.
C) $30.4 \mathrm{~N}$.
D) $40.5 \mathrm{~N}$.
E) $60.5 \mathrm{~N}$.

Question

Quizplus · Accepted Answer

The radial force on the mass is given by $F_r = m a_r = m r \omega^2$, where $m$ is the mass, $r$ is the radius of the circular path, and $\omega$ is the angular speed. In this case, $m = 2.60 \mathrm{~kg}$, $r = 3.50 \mathrm{~m}$, and $\omega = 5.50 \mathrm{rad} / \mathrm{sec}$. Substituting these values into the equation, we get $F_r = (2.60 \mathrm{~kg})(3.50 \mathrm{~m})(5.50 \mathrm{rad} / \mathrm{sec})^2 = 50.1 \mathrm{~N}$.

A 2.60 kg2.60 \mathrm{~kg}2.60 kg Mass Is Moving in a Circular Path with a Constant

A $2.60 \mathrm{~kg}$ Mass Is Moving in a Circular Path with a Constant